(x+7)+(2x-3)=x^2

Solution for (x+7)+(2x-3)=x^2 equation:

Simplifying
(x + 7) + (2x + -3) = x2

Reorder the terms:
(7 + x) + (2x + -3) = x2

Remove parenthesis around (7 + x)
7 + x + (2x + -3) = x2

Reorder the terms:
7 + x + (-3 + 2x) = x2

Remove parenthesis around (-3 + 2x)
7 + x + -3 + 2x = x2

Reorder the terms:
7 + -3 + x + 2x = x2

Combine like terms: 7 + -3 = 4
4 + x + 2x = x2

Combine like terms: x + 2x = 3x
4 + 3x = x2

Solving
4 + 3x = x2

Solving for variable 'x'.

Combine like terms: x2 + -1x2 = 0
4 + 3x + -1x2 = 0

Factor a trinomial.
(4 + -1x)(1 + x) = 0

Subproblem 1
Set the factor '(4 + -1x)' equal to zero and attempt to solve:

Simplifying
4 + -1x = 0

Solving
4 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1x = 0 + -4
-1x = 0 + -4

Combine like terms: 0 + -4 = -4
-1x = -4

Divide each side by '-1'.
x = 4

Simplifying
x = 4
Subproblem 2
Set the factor '(1 + x)' equal to zero and attempt to solve:

Simplifying
1 + x = 0

Solving
1 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + x = 0 + -1
x = 0 + -1

Combine like terms: 0 + -1 = -1
x = -1

Simplifying
x = -1
Solution
x = {4, -1}